a:=( 1, 3, 8, 6)( 2, 5, 7, 4)( 9,33,25,17)(10,34,26,18)(11,35,27,19);
b:=( 9,11,16,14)(10,13,15,12)( 1,17,41,40)( 4,20,44,37)( 6,22,46,35);
c:=(17,19,24,22)(18,21,23,20)( 6,25,43,16)( 7,28,42,13)( 8,30,41,11);
d:=(25,27,32,30)(26,29,31,28)( 3,38,43,19)( 5,36,45,21)( 8,33,48,24);
e:=(33,35,40,38)(34,37,39,36)( 3, 9,46,32)( 2,12,47,29)( 1,14,48,27);
f:=(41,43,48,46)(42,45,47,44)(14,22,30,38)(15,23,31,39)(16,24,32,40);
cube := Group(a,b,c,d,e,f);
One is now ready to compute. For example, the size of the group is determined with
Size(cube);
tells that it is 43252003274489856000.
How many times does a Rubik player have to repeat the combination
a*b^-1*c*e, to get back to the original situation?
Size(Group(a*b^-1*c*e));
Many more examples can be found at the
GAP homepage .